Originally Posted by
mr fantastic Do you know that when the surface is defined in the form
then:
since
and
.
After making the required substitutions your flux integral becomes
, where
is the region of the xy-plane defined by
. I'd suggest switching to polar coordinates to get this double integral.
Note that the region
is found by substituting z = 1 into
.
Of course, you could always switch to cylindrical coordinates at the very start of the problem .......
mr. fantastic, I'd like to suggest something to improve your notation.
Instead of typing
Code:
[tex]\int \int_S F \cdot dS[/tex]
And getting , you can type
Code:
[tex]\iint\limits_S F \cdot dS[/tex]
and get , which looks neater.
--Chris