Originally Posted by

**mr fantastic** Do you know that when the surface is defined in the form

then:

since

and

.

After making the required substitutions your flux integral becomes

, where

is the region of the xy-plane defined by

. I'd suggest switching to polar coordinates to get this double integral.

Note that the region

is found by substituting z = 1 into

.

Of course, you could always switch to cylindrical coordinates at the very start of the problem .......

mr. fantastic, I'd like to suggest something to improve your notation.

Instead of typing

Code:

[tex]\int \int_S F \cdot dS[/tex]

And getting , you can type

Code:

[tex]\iint\limits_S F \cdot dS[/tex]

and get , which looks neater.

--Chris