Hello, weezie23!

I can't quite follow your work . . .

When x = 2, .y .= .ln(8) - 6y .= .ln(4x) - 6

Find the equation of tangent line at x = 2

. . We have a point: .(2, ln(8) - 6)

The derivative is: .y' .=] .1/x

. . At x = 2, the slope is: .m = ½

The equation of the tangent is: . y - [ln(8) - 6] .= .½(x - 2)

. . which simplifies to: . y .= .½x + ln(8) - 7