y= ln4x - 6
find equasion of tangent line at x=2
y' = 1/x find y - ln4(2) - 6 = -3.9
p/s formula = y + 4.9 = x/2 equasion of tangent line @ x=2 is y= x/2 - 4.9
Hello, weezie23!
I can't quite follow your work . . .
When x = 2, .y .= .ln(8) - 6y .= .ln(4x) - 6
Find the equation of tangent line at x = 2
. . We have a point: .(2, ln(8) - 6)
The derivative is: .y' .=] .1/x
. . At x = 2, the slope is: .m = ½
The equation of the tangent is: . y - [ln(8) - 6] .= .½(x - 2)
. . which simplifies to: . y .= .½x + ln(8) - 7