differentiate f(x) = 2xe^x answer I got was 2xe^x + 2e^x = 2e^x(x+1) equal to zero and critical values x=-1
Follow Math Help Forum on Facebook and Google+
Originally Posted by weezie23 differentiate f(x) = 2xe^x answer I got was 2xe^x + 2e^x = 2e^x(x+1) equal to zero and critical values x=-1 Correct! --Chris
View Tag Cloud