differentiate f(x) = 2xe^x

answer I got was 2xe^x + 2e^x = 2e^x(x+1) equal to zero and critical values x=-1

Printable View

- Jul 28th 2008, 11:33 AMweezie23checking answer
differentiate f(x) = 2xe^x

answer I got was 2xe^x + 2e^x = 2e^x(x+1) equal to zero and critical values x=-1 - Jul 28th 2008, 11:34 AMChris L T521