Mr. F, when you take the divergence of a field, you're left with a scalar value...it should be 2x+2y+2z, not 2xi+2yj+2zk...Originally Posted by asi123
What is the Divergence? is it only the Partial derivatives?
Lets say I have a vector field: F=x^2i+y^2j+z^2k, the divergence is F=2xi+2yj+2zk? Mr F says: Yes. Chris says: Not quite. This would be your gradient, but not your divergence...
Yes, the gradient consists of partial derivatives, but note the difference between the values of the gradient and divergence:But still, isnt the gradient already define the partial derivative?
Does this make a little more sense now?
EDIT: I should have made this a little clearer by noting that the gradient can only be applied to scalar fields, as Mr. Fantastic had mentioned earlier.