# Thread: Linear integral

1. ## Linear integral

Is this "legal" what I did? I mean switching to t like this?

2. Originally Posted by asi123
Is this "legal" what I did? I mean switching to t like this?

Some of us access MHF from machines/networks that block imageshack. It would help if jpg's were uploaded to MHF.

RonL

3. Originally Posted by CaptainBlack
Some of us access MHF from machines/networks that block imageshack. It would help if jpg's were uploaded to MHF.

RonL

I try, but it gives the following error:
scan0001.jpg:
This is not a valid image file.

Anyway, I used another service, can u see this one?
Image Hosting

And another thing, is it possible that x=0, according to the point they gave?

10x again.

4. Originally Posted by asi123
I try, but it gives the following error:
scan0001.jpg:
This is not a valid image file.

Anyway, I used another service, can u see this one?
Image Hosting
No, they have blocked all image hosting services.

RonL

5. Originally Posted by CaptainBlack
No, they have blocked all image hosting services.

RonL
\overline{F}=\frac{\sin(y)}{\sqrt{x}}\hat{i}+2\sqr t{x}\hat{j}

L:y=\sqrt{x}

A(0,0)

B(\frac{\pi^2}{4},\frac{\pi}{2})

x=z\Rightarrow{y=\sqrt{z}} 0\leqslant{L}\leqslant\frac{\pi^2}{4}

You beter hope taht whoever has time to help you with this knows LaTeX well

EDIT:

Forgot about this, for those who do have image hosting.

6. Originally Posted by Mathstud28
\overline{F}=\frac{\sin(y)}{\sqrt{x}}\hat{i}+2\sqr t{x}\hat{j}

L:y=\sqrt{x}

A(0,0)

B(\frac{\pi^2}{4},\frac{\pi}{2})

x=z\Rightarrow{y=\sqrt{z}} 0\leqslant{L}\leqslant\frac{\pi^2}{4}

You beter hope taht whoever has time to help you with this knows LaTeX well

EDIT:

Forgot about this, for those who do have image hosting.

10x.

Another thing, as you can see A=(0,0). is it possible? I mean, how can x be 0?