Evaluate attachment
(I uploaded the equation rather than typing it out as my previous post).
Thanks.
Hello,
I've never done it this way, so it's experimental ^^P.S. Anyone who reads this, is there another way to do this w/o L'Hopital's Rule??
When x approaches 0, one can say that t and hence t^3 approaches 0 because it's restricted below by 0 and above by x.
So
Therefore