Originally Posted by

**crabchef** z=x^2 +3y^2 ; x=0, y=1, y=x, z=0

I drew a diagram and figured out that y should be between 1 and x

From the diagram, it looks pretty clear to me that the lower bound of x should be 1. However, I am having difficulty figuring out what the upper bound should be. I would imagine that it should be the intersection between our function z=x^2+3y^2 and either y=x or y=1. However, plugging in z=0 would give me x^2=-3y^2 which seems really bad since I can't take the square root of a negative.

Thanks for your help guys ><