1. ## ∫ye^(y^2)

∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help

2. Originally Posted by crabchef
∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help
$\int ye^{y^2}\,dy$

We don't need parts here. Just make the substitution $u=y^2\implies \frac{du}{2}=y~dy$

Then the integral becomes: $\frac{1}{2}\int e^u\,du$

Evaluate and then resubsitute $u=y^2$ back into the solution.

I hope this clarifies things!

--Chris

3. Originally Posted by Chris L T521
$\int ye^{y^2}\,dy$

We don't need parts here. Just make the substitution $u=y^2\implies \frac{du}{2}=y~dy$

Then the integral becomes: $\frac{1}{2}\int e^u\,du$

Evaluate and then resubsitute $u=y^2$ back into the solution.

I hope this clarifies things!

--Chris
thanks chris! that was very helpful =)

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# Ø§ÙˆØ¬Ø¯ ØªÙƒØ§Ù…Ù„ ye^-y

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