∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?
If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...
thanks for any help
$\displaystyle \int ye^{y^2}\,dy$
We don't need parts here. Just make the substitution $\displaystyle u=y^2\implies \frac{du}{2}=y~dy$
Then the integral becomes: $\displaystyle \frac{1}{2}\int e^u\,du$
Evaluate and then resubsitute $\displaystyle u=y^2$ back into the solution.
I hope this clarifies things!
--Chris