# ∫ye^(y^2)

• Jul 20th 2008, 11:38 AM
crabchef
∫ye^(y^2)
∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help
• Jul 20th 2008, 12:15 PM
Chris L T521
Quote:

Originally Posted by crabchef
∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help

$\int ye^{y^2}\,dy$

We don't need parts here. Just make the substitution $u=y^2\implies \frac{du}{2}=y~dy$

Then the integral becomes: $\frac{1}{2}\int e^u\,du$

Evaluate and then resubsitute $u=y^2$ back into the solution.

I hope this clarifies things! (Sun)

--Chris
• Jul 20th 2008, 12:25 PM
crabchef
Quote:

Originally Posted by Chris L T521
$\int ye^{y^2}\,dy$

We don't need parts here. Just make the substitution $u=y^2\implies \frac{du}{2}=y~dy$

Then the integral becomes: $\frac{1}{2}\int e^u\,du$

Evaluate and then resubsitute $u=y^2$ back into the solution.

I hope this clarifies things! (Sun)

--Chris

thanks chris! that was very helpful =)