∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help

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- Jul 20th 2008, 10:38 AMcrabchef∫ye^(y^2)
∫ye^(y^2)dy => how do I integrate this? Does it have to be done by parts?

If so, how do I need to set that up? I got about this far: u=y^2, du= 2ydy but then I'm not sure what do set dv as...

thanks for any help - Jul 20th 2008, 11:15 AMChris L T521
$\displaystyle \int ye^{y^2}\,dy$

We don't need parts here. Just make the substitution $\displaystyle u=y^2\implies \frac{du}{2}=y~dy$

Then the integral becomes: $\displaystyle \frac{1}{2}\int e^u\,du$

Evaluate and then resubsitute $\displaystyle u=y^2$ back into the solution.

I hope this clarifies things! (Sun)

--Chris - Jul 20th 2008, 11:25 AMcrabchef