First I have to use substitution on this, then integration by parts.
∫ x^3 ln(x^2 + 1) dx
My guess is that y = x^2 + 1
Then dy = 2x dx but then I'm stuck since 2x isn't a 3 degree exponent like in the original integral.
First I have to use substitution on this, then integration by parts.
∫ x^3 ln(x^2 + 1) dx
My guess is that y = x^2 + 1
Then dy = 2x dx but then I'm stuck since 2x isn't a 3 degree exponent like in the original integral.