1. ## Given f(x)=3x^2-4

Given f(x)=3x^2-4, find F(x) "upside down A "FOR ALL" " x epsilon [x,3] if F(0) = 0

a. 17
b. 0
c. 19
d. 4.32

2. Originally Posted by shanniepooh2
Given $f(x)=3x^2-4$, find $F(x)$ $\forall{x}\in[x,3]$ if $F(0)=0$

a. 17
b. 0
c. 19
d. 4.32
This makes no sense? Is this the full question?

3. Originally Posted by Mathstud28
This makes no sense? Is this the full question?
f(x)=3x^2-4, "upside down A "FOR ALL" " x epsilon [2,3] if F(0) = 0

I Accidently place an x instead of a 2 and the "for all" and the x are seperate

4. Please see the previous reply... I accidently place an x instead of a 2 as an integer..

5. Originally Posted by shanniepooh2
f(x)=3x^2-4, "upside down A "FOR ALL" " x epsilon [2,3] if F(0) = 0

I Accidently place an x instead of a 2 and the "for all" and the x are seperate
Just compute $\int_2^{3}\bigg[3x^2-4\bigg]~dx$

6. I was reading Mathstud28's method and decided to try it, but I got 15 as my answer, which is not a choice.

Did I do something wrong?