Given f(x)=3x^2-4

• Jul 14th 2008, 05:40 PM
shanniepooh2
Given f(x)=3x^2-4
Given f(x)=3x^2-4, find F(x) "upside down A "FOR ALL" " x epsilon [x,3] if F(0) = 0

a. 17
b. 0
c. 19
d. 4.32
• Jul 14th 2008, 05:55 PM
Mathstud28
Quote:

Originally Posted by shanniepooh2
Given $f(x)=3x^2-4$, find $F(x)$ $\forall{x}\in[x,3]$ if $F(0)=0$

a. 17
b. 0
c. 19
d. 4.32

This makes no sense? Is this the full question?
• Jul 14th 2008, 06:00 PM
shanniepooh2
Quote:

Originally Posted by Mathstud28
This makes no sense? Is this the full question?

f(x)=3x^2-4, "upside down A "FOR ALL" " x epsilon [2,3] if F(0) = 0

I Accidently place an x instead of a 2 and the "for all" and the x are seperate
• Jul 14th 2008, 06:01 PM
shanniepooh2
Please see the previous reply... I accidently place an x instead of a 2 as an integer..
• Jul 14th 2008, 06:02 PM
Mathstud28
Quote:

Originally Posted by shanniepooh2
f(x)=3x^2-4, "upside down A "FOR ALL" " x epsilon [2,3] if F(0) = 0

I Accidently place an x instead of a 2 and the "for all" and the x are seperate

Just compute $\int_2^{3}\bigg[3x^2-4\bigg]~dx$
• Jul 16th 2008, 12:16 PM
Hahutzy
I was reading Mathstud28's method and decided to try it, but I got 15 as my answer, which is not a choice.

Did I do something wrong?