xF(x)=4x3/4-2

We have to find the horizontal and vertical tangent lines for the
I can not understand how to do any equation with fractions

2. Originally Posted by mted025
4x3/4-2

Can not understand how to do so that I can find max and min
Your expression is completely ambiguous. Do you mean find the derivative of $4x^{3/4} - 2$?

3. ## help with horizontal and vertical tangent lines

I have to find the points at which the graph of F either has a horizontal or vertical line.
the function is F(x)=4x^(3/4)-2

4. Originally Posted by mted025
I have to find the points at which the graph of F either has a horizontal or vertical line.
the function is F(x)=4x^(3/4)-2
Draw the graph. The domain is [0, oo) (why?). It's an increasing function. The tangent is a vertical line at (0, -2) (why?) with equation x = 0. There's no point on the graph at which the tangent is horizontal (why?).

Hint: The derivative is $\left( \frac{3}{4} \right) 4 x^{-1/4} = 3 x^{-1/4} = \frac{3}{x^{1/4}}$.