$\displaystyle y' = -2(3y +4)$

It is separable im lost in how to get the answer,

$\displaystyle y = -4/3 + Ce^-6x$

I tried and made it to $\displaystyle dy = (-6y - 8)dx$ but im unsure as how to get my dy/y for 6lny sigh now im really getting confused. Anyone feel free to shed some light on the case in point.