I got an answer but I am not entirely sure if i was right. can someone please help to verify my answers. thanks
For a body falling under gravity in air, the rate of change of velocity is given by dV/dt = -k(V-P) where P and K are constants. This has a solution: V=P+Ae^(-kt). If the rate of change by dV/dt = -0.02(V-490), find:
a) an equation for V, remembering that initially V=0
b) the velocity after 10 seconds (2dp)
c) the maximum velocity which could be achieved, assuming no outside interference.