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Math Help - rate change

  1. #1
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    rate change

    The volume of a closed cylinder of constant height 8cm is given by V=8(pi)r(squared). The radius of its base is 6cm and is increasing at the rate of 0.04cm/s

    a) at what rate is the volume of the cylinder increasing? (to 2 decimal places)

    b) at what rate is the total surface area of the cylinder increasing (to 2 decimal places)

    I just need to verify my answers with someone quickly. thanx.
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  2. #2
    MHF Contributor kalagota's Avatar
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    Quote Originally Posted by chrisgo View Post
    The volume of a closed cylinder of constant height 8cm is given by V=8(pi)r(squared). The radius of its base is 6cm and is increasing at the rate of 0.04cm/s

    a) at what rate is the volume of the cylinder increasing? (to 2 decimal places)
    just solve for \frac{dV}{dt} and plug in r and \frac{dr}{dt}

    16\pi (6) (0.04)

    Quote Originally Posted by chrisgo View Post
    b) at what rate is the total surface area of the cylinder increasing (to 2 decimal places)

    I just need to verify my answers with someone quickly. thanx.
    also just solve for \frac{dT}{dt} and plug in \frac{dr}{dt}
    where T = 2\pi r^2 + 2\pi r h
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