Originally Posted by Luckyjoshua
Thus,
Thus,
Let,
Then,
Now you can solve quadradic.
----
This should not be called a calculus thread. Because it has nothing to do with calculus (unless you are doing hyperbolic functions).
You have a good point. So, since cosh(x) is symmetric about the y-axis the solution transforms into .Originally Posted by ThePerfectHacker
Do you (TPH) have another method to get to this point directly? (If so I would be interested to see it. Really!)
-Dan
Oops! Didn't see your post under mine! Gotcha!