f inceases most slowly if f'(x)=2, so the smallest possible value for f(4) is:Originally Posted by Nimmy
Let me give a more reasonable explanation.Originally Posted by Nimmy
Honestly, I do not understand what CaptainBlank is doing.
You are going to use the most impostant theorem in calculus, mean-value theorem.
To remind you.
If a function is countinous on and diffrenciable on then there exists are number such as,
Now comes the answer.
Since for all you know that the function is diffrenciable for any (because it exists between 2 and 3). Furthermore, the function is countinous for any because diffrenciability implies counintuity.
Consider on the interval . By the previous explanation we have shown this function satisfies the conditions of the mean value theorem. Thus there is a such as,
Therefore the largest possible value of is the largest possible value of which is 3. Thus,
And the smallest possible values is similarly,
It is simply that the smallest possible value for f'(x) is 2 (over the interval [1,4] ) according to the problem statement, so the smallest possible change in f(x) from x = 1 to x = 4 is 2*(4-1) = 6.Originally Posted by ThePerfectHacker
You basically said the same thing, just with a lot more precision.
Tsk, tsk! You aren't supposed to edit quotes!
Given that and for all ,
what is the smallest possible value for ?
This is what the Captain meant . . .Code:| Q | * (4,?) | : | : | P : | * : | (1,3) : | : | : - - + - + - + - + - + - - | 1 2 3 4
We are given point
When , we have a point
. . the slope of the graph from to is between and .
The lowest occurs when the slope is exactly 2 (all the way).
This puts at .
Therefore, the minimum value of is
I think my answer explains why the answer is what it is, with such anOriginally Posted by topsquark
explanation the answer is obvious.
Since symbolic manipulation is error prone, what the answer emerges at
the end of a long chain of symbolic games leaves considerable doubt as
to the correctness of the argument without considerable checking.
Not that the rigorous derivation of the result is not needed some times
to confirm the obvious.
I have an amusing anecdote about this sort of thing, but I won't repeat it
here as I suspect I'm the only one who will find it amusing.