Originally Posted by

**JonathanEyoon** I'm not certain why but I can't seem to get the right answer no matter how many times I run through this

Integrate (x^2) / ((x - 3)(x + 2)^2)

(A / x - 3) + (B / x + 2) + (C / (x + 2)^2)

My values for A and C seem correct from the method I was taught by the professor

A = 9 / 25 C = - 4 / 5

Now to get B, I equated for cubics.

x^2 = ((9/25)(x + 2)^3) + B(x - 3)(x + 2)^2 - (4/5)(x - 3)(x + 2)

Now the B I got was - 9 / 25.

Can someone tell me if I've done this right so far? Thanks