Hello! If sin y = 2 sin x, show that (dy/dx)^2 = 1 + 3 sec^2 y I tried implicit differentiation and I found dy/dx = 2 cos x / 2 cos y, but I don't know how to continue from there... Thank you for helping!!
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Originally Posted by Tangera Hello! If sin y = 2 sin x, show that (dy/dx)^2 = 1 + 3 sec^2 y I tried implicit differentiation and I found dy/dx = 2 cos x / 2 cos y, but I don't know how to continue from there... Thank you for helping!! $\displaystyle \frac{dy}{dx} = \frac{2\cos x}{\cos y}$ $\displaystyle \left(\frac{dy}{dx}\right)^2 = \frac{4\cos^2 x}{\cos^2 y}$ what is $\displaystyle \cos^2 x =?$
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