$\displaystyle \int \frac {x^2}{(x-3)(x+2)^2} ~dx = \frac {A}{x-3} + \frac {B}{x+2} + \frac {C}{(x+2)^2}$

That is where I am at so far, and I just need a little help with finding the common denominator. Normally you would multiply A by the denominators of both B and C, but what about in this case? Since they are practically the same. Would I multiply A by $\displaystyle (x+2)(x+2)^2$ or just by (x+2)?