$\displaystyle \int_{1}^{2} \frac {4y^2-7y-12}{y(y+2)(y-3)} ~dx$

So far I have $\displaystyle \frac {A}{y} + \frac {B}{(y+2)} + \frac {C}{(y-3)}$

You have to combine them right and get a common denominator? So I have $\displaystyle 4y^2-7y-12 = A(y+2)(y-3) + B(y)(y-3) + C(y)(y+2)$

But what do I do from here? So far, we have only done examples in class with 2 variables, A and B, but not with C. So its throwing me off.