Use taylor polynomials about 0 to evaluate cos(0.52) to 4 deciamal places, showing all your working.

What I did;

Since the taylor polynomial about 0 for cosine function is

p n (x) = 1-1/2!x^2 + 1/4!x^4- 1/6!x^6+.....1/n!x^n

Hence (did all working)

p2(0.52) = 0.8646

P4(0.52) = 0.867846

p6(0.52) = 0.867819

p8(0.52) = 0.867819

So cos(0.52) = 0.8678