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Math Help - is this correct?

  1. #1
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    is this correct?

    {4 - 5e^ - 5t + (e^2t)/3}dt

    I got
    4t + e^-5t + (e^2t)/6
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  2. #2
    MHF Contributor Mathstud28's Avatar
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    Quote Originally Posted by 10164064 View Post
    {4 - 5e^ - 5t + (e^2t)/3}dt

    I got
    4t + e^-5t + (e^2t)/6
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by 10164064 View Post
    {4 - 5e^ - 5t + (e^2t)/3}dt

    I got
    4t + e^-5t + (e^2t)/6
    You can check this yourself by differentiating 4t + e^{-5t} + e^{2t}/6, you should get your integrand 4 - 5e^{- 5t} + e^{2t}/3.

    Also since this is an indefinite integralb there should be an arbitary constant added so you should have:

    4t + e^{-5t} + e^{2t}/6+c

    RonL
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