{4 - 5e^ - 5t + (e^2t)/3}dt I got 4t + e^-5t + (e^2t)/6
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Originally Posted by 10164064 {4 - 5e^ - 5t + (e^2t)/3}dt I got 4t + e^-5t + (e^2t)/6
Originally Posted by 10164064 {4 - 5e^ - 5t + (e^2t)/3}dt I got 4t + e^-5t + (e^2t)/6 You can check this yourself by differentiating , you should get your integrand . Also since this is an indefinite integralb there should be an arbitary constant added so you should have: RonL
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