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Math Help - Integration?

  1. #1
    Super Member fardeen_gen's Avatar
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    Integration?

    { ∫ from 0 to L of x(M/L) dx}/{ ∫ from 0 to M of dm} = ?

    I think the answer is L/2. Am I right?

    Edit:
    My bad. I entered wrong data in the numerator.I have corrected it now.
    Last edited by fardeen_gen; July 1st 2008 at 09:07 AM. Reason: Entered wrong question!
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  2. #2
    Super Member wingless's Avatar
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    \frac{\int_0^L \frac{M}{L}~dx}{\int_0^M~dm}=\frac{\frac{M}{L}x~\b  igg |_{x=0}^L}{m~\bigg |_{m=0}^M}= \frac{M-0}{M-0}=1
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  3. #3
    Moo
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    Hello,

    Quote Originally Posted by fardeen_gen View Post
    { ∫ from 0 to L of x(M/L) dx}/{ ∫ from 0 to M of dm} = ?

    I think the answer is L/2. Am I right?

    Edit:
    My bad. I entered wrong data in the numerator.
    Yes it is
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  4. #4
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    Quote Originally Posted by fardeen_gen View Post
    { ∫ from 0 to L of x(M/L) dx}/{ ∫ from 0 to M of dm} = ?

    I think the answer is L/2. Am I right?

    Edit:
    My bad. I entered wrong data in the numerator.I have corrected it now.
    \frac{\int_0^L \frac{M}{L}x \ \mathrm{d}x}{\int_0^M \mathrm{d}m} =\frac{\left[ \frac{Mx^2}{2L}\right]_{x=0}^L}{\left[m\right]_{m=0}^M } = \frac{\frac{ML^2}{2L} - 0}{M-0} = \frac{\frac{ML}{2} - 0}{M} = \frac{ML}{2M} =\frac{L}{2}
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  5. #5
    Super Member wingless's Avatar
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    Quote Originally Posted by Air View Post
    \frac{\int_0^L \frac{M}{L}x \ \mathrm{d}x}{\int_0^M \mathrm{d}m} =\frac{\left[ \frac{Mx^2}{2L}\right]_{x=0}^L}{\left[m\right]_{m=0}^M } = \frac{\frac{ML^2}{2L} - 0}{M-0} = \frac{\frac{ML}{2} - 0}{M} = \frac{ML}{2M} =\frac{L}{2}
    Something must be wrong with my eyes, I can't read anything except LaTeX these days..
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  6. #6
    Moo
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    Quote Originally Posted by wingless View Post
    Something must be wrong with my eyes, I can't read anything except LaTeX these days..
    The OP said he posted it wrong in a first time
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