What is average value of sin x over x = pi to x = 2pi ?
My answer: -2/pi
Is it correct?
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Hi Originally Posted by fardeen_gen Is it correct? Yes it is.
Originally Posted by flyingsquirrel Hi
Yes it is. Geez, I am really rusty. I'm getting -1/pi.
INT(pi to 2pi)[sinX]dx
= [-cosX](pi to 2pi)
= -cos(2pi) +cos(pi)
= -1 +0
So average = -1/(2pi -pi) = -1/pi
Can someone please show me how it should be -2/pi?
cos pi is -1.
Originally Posted by fardeen_gen cos pi is -1. Yes, of course!
I was thinking of cos pi/2.
I'd have to shake off more rust flakes from my Math brain.
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