What is average value of sin x over x = pi to x = 2pi ? My answer: -2/pi Is it correct?
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Hi Originally Posted by fardeen_gen Is it correct? Yes it is.
Originally Posted by flyingsquirrel Hi Yes it is. Geez, I am really rusty. I'm getting -1/pi. INT(pi to 2pi)[sinX]dx = [-cosX](pi to 2pi) = -cos(2pi) +cos(pi) = -1 +0 = -1 So average = -1/(2pi -pi) = -1/pi Can someone please show me how it should be -2/pi?
cos pi is -1.
Originally Posted by fardeen_gen cos pi is -1. Yes, of course! I was thinking of cos pi/2. I'd have to shake off more rust flakes from my Math brain. Thanks.
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