1. ## IMolicit differentiation

one more im not sure about

e^(x+y) +x-y^2=3

it is e^(x+y)+x-y^2=3

2. Originally Posted by gabet16941
one more im not sure about

e^x+y +x-y^2
$e^x+y'-2y\cdot{y'}=0$

I assume

3. Originally Posted by gabet16941
one more im not sure about

e^x+y +x-y^2
Originally Posted by Mathstud28
$e^x+y'-2y\cdot{y'}=0$

I assume
err.. herm..

$\frac{d}{dx}\left( e^x+y+x-y^2\right)=e^x+\frac{dy}{dx}+1-2y\frac{dy}{dx}$

RonL

4. I would say $e^{x+y}+(x-y)^2$

Te derivative is $\underbrace{(1+y')e^{x+y}}_{\text{chain rule}}+\underbrace{2(1-y')(x-y)}_{\text{chain rule}}$

5. Originally Posted by gabet16941
one more im not sure about

e^x+y +x-y^2
Please use brackets to make the expression unambiguous. The normal precedence of operators means that without brackets this represents:

$e^x + y + x + y^2$

if you intend anything else you need to use brackets.

RonL

6. Originally Posted by Moo
I would say $e^{x+y}+(x-y)^2$

Te derivative is $\underbrace{(1+y')e^{x+y}}_{\text{chain rule}}+\underbrace{2(1-y')(x-y)}_{\text{chain rule}}$
But you are only guessing the OPs intention, that is not what they wrote?!
RonL

7. Originally Posted by CaptainBlack
But you are only guessing the OPs intention, that is not what they wrote?!
RonL
Isn't "would" a sign of "condition" ? lol

It doesn't matter actually ^^

See ya