Hi everyone,
I would like to know if I did any mistake in my calculation?
Here is the question and my answer:
(a Using equation:
∫ (f(x))n f’(x) dx = 1/n+1(f(x))n+1 + c (n≠-1)
show that
∫ cos x dx = - 1 + c,
(2 + sin x)2 2+ sin x
Where c is an arbitrary constant.
∫ cos x dx = - sin ∫ (x) dx
(2 + sin x)2 (2+sinx)2
= x = - 1
(2+sin x)2 2+sin x + c
Thanks for your help