Hi everyone,

I would like to know if I did any mistake in my calculation?

Here is the question and my answer:

(a Using equation:

∫ (f(x))n f’(x) dx = 1/n+1(f(x))n+1 + c (n≠-1)

show that

∫cos xdx = -1+ c,

(2 + sin x)2 2+ sin x

Where c is an arbitrary constant.

∫cos xdx = - sin ∫(x)dx

(2 + sin x)2 (2+sinx)2

=x= -1

(2+sin x)2 2+sin x + c

Thanks for your help