# straight

• June 29th 2008, 07:23 AM
Apprentice123
straight
At what point the straight that passes by A(2,3,4) and B(1,0,-2) intercepts the xy plane?

$(\frac{4}{3},1,0)$
• June 29th 2008, 07:33 AM
galactus
The parametric line equations are:

$x=1+t, \;\ y=3t, \;\ z=-2+6t$

In order to intersect the xy plane, then z must = 0.

So, from z:

$-2+6t=0, \;\ t=1/3$

Insert this into x and y and we get:

$x=4/3, \;\ y=1, \;\ z=0$