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Thread: Application of calculus?

  1. June 29th 2008, 07:04 AM #1
    fardeen_gen
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    Application of calculus?

    Power supplied by a cell to a resistance R is given by P = [E/(R + r)]^2 * R. E and r, remain constant. For what value of R, maximum power is supplied to resistance R?

    Ans: R=r
    Can anyone explain the method?
    Last edited by fardeen_gen; June 29th 2008 at 07:05 AM. Reason: Addition of info
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  2. June 29th 2008, 07:10 AM #2
    galactus
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    If you differentiate, you get:

    \frac{E^{2}(r-R)}{(R+r)^{3}}

    Setting to 0 and solving we see that:

    (r-R)=0, \;\ \therefore{R=r}
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