I don't even understand the wording of this. Also arcSINx? Denote by y=arcsinx, -1< or = x < or = 1, the inverse of y=sinx with x between -pi/2 and pi/2. Show that d/dx arcsinx = 1/sqrt(1-x^2) with x between -1 and 1
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Hello, Originally Posted by SportfreundeKeaneKent I don't even understand the wording of this. Also arcSINx? Denote by y=arcsinx, -1< or = x < or = 1, the inverse of y=sinx with x between -pi/2 and pi/2. Show that d/dx arcsinx = 1/sqrt(1-x^2) with x between -1 and 1 arcsin x denotes the inverse function, as stated above. This means : . You want . I'll do it the other way round : Here, , because -pi/2<=y<=pi/2 --> cos y is positive. , because . Therefore Any question ?
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