Finding the equation of the plan that passes the straight r: $\displaystyle \frac{(x-1)}{3}=\frac{(y-3)}{2}=\frac{(z+2)}{-1}$ and is parallel to the straight s: x-y+z-3=0 x+y-z+5=0 answer: x-y+z+4=0
Follow Math Help Forum on Facebook and Google+
How do I find the vector of directional straight (s)?
View Tag Cloud