1, find s in terms of t if ds/dt=3t-8/tsquared and s=1and1/2 when t= 1
1, square root of (2-3x)dx
2, given that dy/dx=3/x-2 and y =10 when x=0, find an expression for y in terms of x
1, find( 2e^3x-e^-x) dx
The first one is, I presume, to solve
This equation is separable:
We know that s(1) = 3/2, so
Solve for C.
For the second one I presume you are trying to integrate?
Then your integral becomes
For the third I presume this is
(Please use parenthesis!)
This is, again, a separable equation:
Integrate both sides by using the substitution u = x - 2.
I presume the last one is an integration as well and is
(Again, please use parenthesis!)
Split this into two parts:
For the first integral let y = 3x and the second let u = -x.