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Math Help - Find rectangle with largest area

  1. #1
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    Find rectangle with largest area

    I attempted to solve this problem. I just want to make sure that I did it properly.

    The parabola is y=8-x^2
    Rectangle = 2x(8-x^2)
    =16-6x^2 (i got this by first distributing 2x then finding the derivative)
    X= Sqrt(8/3)

    Since the base is 2x, the base of this rect. would be 2Sqrt(8/3)
    then since y is a f(x). I get 16/3

    The dimensions of my rectangle would be H= 16/3 and L = 2Sqrt(8/3)
    My area would be 17.42

    Thank you!
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  2. #2
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    Quote Originally Posted by PensFan10 View Post
    I attempted to solve this problem. I just want to make sure that I did it properly.

    The parabola is y=8-x^2
    Rectangle = 2x(8-x^2)
    =16-6x^2 (i got this by first distributing 2x then finding the derivative)
    X= Sqrt(8/3)

    Since the base is 2x, the base of this rect. would be 2Sqrt(8/3)
    then since y is a f(x). I get 16/3

    The dimensions of my rectangle would be H= 16/3 and L = 2Sqrt(8/3)
    My area would be 17.42

    Thank you!
    You have it done correctly, but before you hand something like this in for credit PLEASE organize your work more clearly!

    -Dan
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  3. #3
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    Okay thanks. I will see what I can do about the organization problem :P
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