Hello. I'm doing study for a Maths test we have coming up. And i have been stumped on this Question. Solve $\displaystyle ln(x) = x^3 - 2$ by using two applications of Newtons method Thanks in advance.
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Originally Posted by name101 Hello. I'm doing study for a Maths test we have coming up. And i have been stumped on this Question. Solve $\displaystyle ln(x) = x^3 - 2$ by using two applications of Newtons method Thanks in advance. Let $\displaystyle f(x) = \ln x - x^3 +2$.. Then $\displaystyle f'(x) = \frac{1}{x} - 3x^2$ Let$\displaystyle x_0$ be your initial guess.. $\displaystyle x_1 = x_0 - \frac{f(x_0)}{f'(x_0)}$ and $\displaystyle x_2 = x_1 - \frac{f(x_1)}{f'(x_1)}$
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