i dont get how this (2x-3)^4 (3) + 3x (4) (2x-3)^3 (2) is simplified to this 3(2x-3)^3 (2x-3+8x) can you please help show the step in between the two equations thanks
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Originally Posted by Fibonacci i dont get how this $\displaystyle (2x-3)^4 (3) + 3x (4) (2x-3)^3 (2)$ is simplified to this $\displaystyle 3(2x-3)^3 (2x-3+8x)$ can you please help show the step in between the two equations thanks $\displaystyle 3.(2x-3)^4+3.(2x-3)^3(4)(2)(x)$ $\displaystyle 3.(2x-3)^4+3.(2x-3)^3(8x)$ Take $\displaystyle 3.(2x-3)^3$ as a common factor, $\displaystyle 3(2x-3)^3[(2x-3)+8x] = 3(2x-3)^3 (2x-3+8x)$
Last edited by rednest; Jun 21st 2008 at 05:26 AM.
Originally Posted by rednest $\displaystyle 3.(2x-3)^4+3.(2x-3)^4(4)(2)(x)$ $\displaystyle 3.(2x-3)^4+3.(2x-3)^4(8x)$ Take $\displaystyle 3.(2x-3)^3$ as a common factor, $\displaystyle 3(2x-3)^3[(2x-3)+8x] = 3(2x-3)^3 (2x-3+8x)$ Just a case of a typo: Note that the first and second lines have the exponent of (2x - 3) as 4 in the second term. This exponent should be 3. -Dan
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