Finding the equations of the straight (m) through the point M (3,2,1) and is coplanar with the straight (l) and orthogonal to the straight (s), and (l): and (s): (x, y, z) = (-1.2,-3) + t(3,5,6)
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That can't be right. It doesn't contain M.
Sorry. The professor drew up the issue this way, which way to calculate?
Excuse the language is that I'm Brazilian
Perhaps you should start by finding the Plane containing m, M, and l. How do you propose to do that?
Language Note: I think it should be "line", not "straight". Good try, though.
Sorry the correct answer is:
x-2 = y-1/-1 = z-1 / 2.
Because I do coplanar the product mix of (w, l, MPl)-2x +2 = y +2 z = 0
And being orthogonal to (s) 3x +5 and +6 z = 0
I can assign a value to X and discover the other unknown?
Originally Posted by Apprentice123 the product mix of (w, l, MPl) Sorry, I cannot tell what this means. Is it a Cross Product, maybe?
ok. I managed to solve
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