Finding the equations of the straight (m) through the point M (3,2,1) and is coplanar with the straight (l) and orthogonal to the straight (s), and (l): $\displaystyle x-2=\frac{y-1}{-1}=\frac{z-1}{2}$ and (s): (x, y, z) = (-1.2,-3) + t(3,5,6)

Answer:

$\displaystyle \frac{x-3}{3}=y-3=\frac{z+2}{-2}$