sinh

**kate45** · June 18th 2008, 08:54 PM

hi there,

can anyone help me with the derivative of sinh(3x)

**TheEmptySet** · June 18th 2008, 08:59 PM

Originally Posted by kate45

hi there,

can anyone help me with the derivative of sinh(3x)

$\sinh(3x)=\frac{e^{3x}-e^{-3x}}{2}$

$\cosh(3x)=\frac{e^{3x}+e^{-3x}}{2}$

$\frac{d}{dx}\sinh(3x)=\frac{d}{dx}\left( \frac{e^{3x}-e^{-3x}}{2}\right)=3\left( \frac{e^{3x}+e^{-3x}}{2}\right)=3\cosh(3x)$

**kalagota** · June 19th 2008, 06:15 AM

or simply, if you already know the derivative of sinh x, just apply chain rule..

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