Hi guys, need some help on these:
1. $\displaystyle \int x (lnx) dx$
2. $\displaystyle \int x(cos5x)dx$
Let,Originally Posted by c_323_h
$\displaystyle u=\ln x$ and, $\displaystyle v'=x$
Thus,
$\displaystyle u'=1/x$ and, $\displaystyle v=(1/2)x^2$
Thus,
$\displaystyle \frac{1}{2}x^2\ln x-\int \frac{1}{2} xdx$
Thus,
$\displaystyle \frac{1}{2}x^2\ln x-\frac{1}{4}x^2+C$
Let,Originally Posted by c_323_h
$\displaystyle u=x$ and $\displaystyle v'=\cos 5x$
Thus,
$\displaystyle u'=1$ and $\displaystyle v=\frac{1}{5}\sin 5x$
Thus,
$\displaystyle \frac{1}{5}x\sin 5x-\int \frac{1}{5}\sin 5xdx$
Thus,
$\displaystyle \frac{1}{5}x\sin 5x+\frac{1}{25}\cos 5x+C$
(I am the quickest integrator in the west!)
$\displaystyle \int x^n=\frac{x^{n+1}}{n+1}, n\not =-1$Originally Posted by c_323_h
Thus,
$\displaystyle \int xdx=\frac{1}{2}x^2$ but then you need to multiply by $\displaystyle \frac{1}{2}$ thus,
$\displaystyle \frac{1}{2}\cdot \frac{1}{2}x^2=\frac{1}{4}x^2$