I need to find the first 2 orders of the taylor series on the expression below. sqrt(Psi_s0 + Phi_t*exp((Psi_s0-2*Phi_F - V_SB)/Phi_t)) where Phi_t*exp((Psi_s0-2*Phi_F - V_SB)/Phi_t) is defined as Xi, and the taylor series is around Xi = 0.
Last edited by was1984; Jun 15th 2008 at 09:53 PM.
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Originally Posted by was1984 I need to find the first 2 orders of the taylor series on the expression below. sqrt(Psi_s0 + Phi_t*exp((Psi_s0-2*Phi_F - V_SB)/Phi_t)) where Phi_t*exp((Psi_s0-2*Phi_F - V_SB)/Phi_t) is defined as Xi, and the taylor series is around Xi = 0. This is unreadable, ??
Yes, thank you, that is correct.
Originally Posted by was1984 Yes, thank you, that is correct. What is the variable in which we are differentiating in respect to? I will assume it is Then let be equal to the above expression, then the second order polynomial would be
The variable we are differentiating with respect to is Xi, which is the second term under the square root.
I'll try to elaborate. We are setting Then we are solving the series around So I actually want expand an equation of the form for , and I only need the first two terms, fortunately.
Last edited by was1984; Jun 15th 2008 at 09:37 PM.
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