How do you integrate this? Thanks in advance.

Printable View

- June 15th 2008, 03:38 AMSimplicityIntegration By Parts?

How do you integrate this? Thanks in advance. - June 15th 2008, 03:41 AMMoo
Hello,

By the substitution :

:)

How can you know it's this way ? Because you can notice that the derivative of is .

In front of the exponential, we have

So you have something like , k is a constant (here )

Here, two methods :

- you substitute v=u(x)

- you recognize the derivative of

(Wink)