integrate x^5/2 In x dx

f(x) = In x

g^1(x) = x^5/2

f^1 (x) = 1/x

g(x) = 2/7 x^7/2

Integral of f(x) g^1 (x) dx = Inx.2/7x^7/2 - Integral of 1/x .2/7x^7/2 dx =

2/7x^7/2.Inx -4/49x^7/2

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- Jul 15th 2006, 07:11 AMfair_lady0072002Integration, please check
integrate x^5/2 In x dx

f(x) = In x

g^1(x) = x^5/2

f^1 (x) = 1/x

g(x) = 2/7 x^7/2

Integral of f(x) g^1 (x) dx = Inx.2/7x^7/2 - Integral of 1/x .2/7x^7/2 dx =

2/7x^7/2.Inx -4/49x^7/2 - Jul 15th 2006, 07:53 AMgalactus
Looks good.

You could put it in this form if you like:

$\displaystyle \frac{2x^{\frac{7}{2}}(7ln(x)-2)}{49}$ - Jul 15th 2006, 08:14 AMfair_lady0072002
Thanx for that Galactus.....

I think I had left out .....+ c - Jul 15th 2006, 09:16 AMgalactus
Semantics.