$\displaystyle \int \frac{x}{(x^2-1)^\frac12} \ \mathrm{d}x$

There is something really simple that I am not seeing? (Worried) Help please, Thanks in advance.

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- Jun 13th 2008, 04:11 AMSimplicityIntegration: Fraction With 'x' Variable
$\displaystyle \int \frac{x}{(x^2-1)^\frac12} \ \mathrm{d}x$

There is something really simple that I am not seeing? (Worried) Help please, Thanks in advance. - Jun 13th 2008, 04:26 AMIsomorphism
- Jun 13th 2008, 05:06 AMcolby2152
- Jun 13th 2008, 06:27 AMKrizalid
Or make $\displaystyle z^2=x^2-1.$ :(