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Math Help - integration

  1. #1
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    integration

    how do u integrate:


    from 0 to 60?

    the 3600 is really throwing me off. without it i can do the problem just fine. wut i did was break the problem up into 1.2^x/3600 + 1/3600. then i know that the 1/3600 becomes x/3600 but i dunno wut to do for the 1.2^x/3600.

    is there a reverse quotient rule to help me deal with problems like this?
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  2. #2
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    \int_{0}^{60} \frac{1.2^{x} + 1}{3600} \: dx

    This property should help: \int cf(x) \: dx = c \int f(x) dx where c is a contant

    Imagine the constant in your integral as \frac{1}{3600}. So:
    \int_{0}^{60} \frac{1.2^{x} + 1}{3600} \: dx = \frac{1}{3600} \int_{0}^{60} \left(1.2^{x} + 1\right) \: dx
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  3. #3
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    thanks! now i know how to do it
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  4. #4
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    Quote Originally Posted by chukie View Post
    thanks! now i know how to do it
    You don't know to take out a factor but you do know how to find:


    \int 1.2^x~dx?

    Now why do I find that improbable?

    \int 1.2^x ~dx=\int e^{\ln (1.2)x}~dx=\frac{1}{\ln(1.2)} e^{\ln(1.2)x}+C=\frac{1.2^x}{\ln(1.2)}+C

    RonL
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