# Thread: integration

1. ## integration

how do u integrate:

from 0 to 60?

the 3600 is really throwing me off. without it i can do the problem just fine. wut i did was break the problem up into 1.2^x/3600 + 1/3600. then i know that the 1/3600 becomes x/3600 but i dunno wut to do for the 1.2^x/3600.

is there a reverse quotient rule to help me deal with problems like this?

2. $\displaystyle \int_{0}^{60} \frac{1.2^{x} + 1}{3600} \: dx$

This property should help: $\displaystyle \int cf(x) \: dx = c \int f(x) dx$ where c is a contant

Imagine the constant in your integral as $\displaystyle \frac{1}{3600}$. So:
$\displaystyle \int_{0}^{60} \frac{1.2^{x} + 1}{3600} \: dx = \frac{1}{3600} \int_{0}^{60} \left(1.2^{x} + 1\right) \: dx$

3. thanks! now i know how to do it

4. Originally Posted by chukie
thanks! now i know how to do it
You don't know to take out a factor but you do know how to find:

$\displaystyle \int 1.2^x~dx$?

Now why do I find that improbable?

$\displaystyle \int 1.2^x ~dx=\int e^{\ln (1.2)x}~dx=\frac{1}{\ln(1.2)} e^{\ln(1.2)x}+C=\frac{1.2^x}{\ln(1.2)}+C$

RonL