How do you find the the integral of sin(√x)/√x??
$\displaystyle \int\frac{\sin(\sqrt{x})}{\sqrt{x}}dx=2\int\frac{\ sin(\sqrt{x})}{2\sqrt{x}}dx$
Is it more obvious now?
If not
Let $\displaystyle \xi=\sqrt{x}$
So then $\displaystyle d\xi=\frac{1}{2\sqrt{x}}$
So we have
$\displaystyle 2\int\sin(\xi)d\xi$
Can you go from there?