Results 1 to 2 of 2

Math Help - calc3 concept

  1. #1
    Junior Member
    Joined
    Apr 2008
    Posts
    30

    calc3 concept

    given a twice differentiable function y = f(x), determine its curvature at a relative extremum. Can the curvature ever be greater than it is at a relative extremum? why or why not....

    i cannot picture this????
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by chris25 View Post
    given a twice differentiable function y = f(x), determine its curvature at a relative extremum. Can the curvature ever be greater than it is at a relative extremum? why or why not....

    i cannot picture this????
    The curvature of a plain curve given by an explicit equation y=f(x) is:

    \kappa=\frac{|y''|}{(1+y'^2)^{3/2}}

    so at a local extremum y'(x)=0, so the curvature becomes:

    \kappa=|y''|

    at such a point.

    The curvature can be smaller than that at a local extrema, but I will leave it to you to work out why.

    RonL
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. The concept behind sin(π/2-Φ)=cos(Φ)
    Posted in the Trigonometry Forum
    Replies: 11
    Last Post: July 30th 2013, 04:59 AM
  2. Replies: 2
    Last Post: June 16th 2011, 11:18 AM
  3. I need some advice for calc3
    Posted in the Calculus Forum
    Replies: 1
    Last Post: October 2nd 2009, 03:12 PM
  4. calc3 (projectile motion)
    Posted in the Calculus Forum
    Replies: 1
    Last Post: February 15th 2009, 02:44 PM
  5. Replies: 3
    Last Post: February 15th 2009, 09:43 AM

Search Tags


/mathhelpforum @mathhelpforum