Are there any functions, other than f(x)=Constant, satisfy the relation:

f(kx) = f(x), with the constant k>1?

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- June 10th 2008, 04:19 AMlinshiFunctions that satisfy a relation.
Are there any functions, other than f(x)=Constant, satisfy the relation:

f(kx) = f(x), with the constant k>1? - June 10th 2008, 09:23 AMOpalg
Here's how to do it for k=2. Define f(x) in any way you like, for x in the interval 1≤x<2. Then for every (positive or negative) integer n, define (for 1≤x<2). This function will even be continuous (except at 0), provided that f(x) is continuous in the interval [1,2) and . But it will not be continuous at 0 unless f is constant.

The same construction will work for any k>1, if you define f arbitrarily in the interval [1,k) and then define . - June 10th 2008, 12:53 PMtopsquark