Please Help!
Find the point P where the line x=1+t y=2t z=-3t intersects the plane x+y-z=-2
Find the distance from the point (-1,2,3) to the plane -1x+0y-2z=5
plug x,y,z into the equation of the plane to get
$\displaystyle (1+t)+(2t)-(-3t)=-2 \iff 6t+1=-2 \iff t=-\frac{1}{2}$
Plug this value into the parametric equation to find the point.
for part b write the plane is this form
$\displaystyle ax+by+cz+d=0$ and use the formula from this link
Point-Plane Distance -- from Wolfram MathWorld
I hope this helps.