Two equations and three unknowns so infinite number of solutions (therefore there's a parameter). There are an infinite number of ways of expressing the answer. One such is to start by letting y = t, say, where t is any real number.

Then:

2x + z = 5 - t .... (1)

3x + 2z = 8 - 2t .... (2)

Solve (1) and (2) simultaneously for x and z in terms of t. I suggest 2 (1) - (2):

x = 2.

Now substitute x = 2 into (1) and solve for z.